When we have circuits with capacitors and/or inductors as well as resistors and sources, Thévenin and Mayer-Norton equivalent circuits can still be defined by using impedances and complex amplitudes for voltage and currents. For any circuit containing sources, resistors, capacitors, and inductors, the input-output relation for the complex amplitudes of the terminal voltage and current is with . Thus, we have Thévenin and Mayer-Norton equivalent circuits as shown in [link].
Let's find the Thévenin and Mayer-Norton equivalent circuits for [link]. The open-circuit voltage and short-circuit current techniques still work, except we use impedances and complex amplitudes. The open-circuit voltage corresponds to the transfer function we have already found. When we short the terminals, the capacitor no longer has any effect on the circuit, and the short-circuit current equals . The equivalent impedance can be found by setting the source to zero, and finding the impedance using series and parallel combination rules. In our case, the resistor and capacitor are in parallel once the voltage source is removed (setting it to zero amounts to replacing it with a short-circuit). Thus, . Consequently, we have Again, we should check the units of our answer. Note in particular that must be dimensionless. Is it?